Advertisements
Advertisements
Question
The principal value of `tan^-1 sqrt(3)` is ______.
Solution
The principal value of tan^-1 sqrt(3)` is `pi/3`.
Explanation:
`tan^-1 sqrt(3) = tan^-1(tan pi/3)`
= `pi/3 ∈ ((-pi)/2, pi/2)`
APPEARS IN
RELATED QUESTIONS
Find the value of `tan^(-1) sqrt3 - cot^(-1) (-sqrt3)`
Find the principal value of the following:
`sin^-1(tan (5pi)/4)`
Find the principal value of the following:
`sec^-1(2sin (3pi)/4)`
Find the principal value of the following:
`cosec^-1(2cos (2pi)/3)`
Find the principal value of the following:
`cot^-1(-1/sqrt3)`
if sec-1 x = cosec-1 v. show that `1/x^2 + 1/y^2 = 1`
Solve for x, if:
tan (cos-1x) = `2/sqrt5`
Find the principal value of cos–1x, for x = `sqrt(3)/2`.
Find the values of x which satisfy the equation sin–1x + sin–1(1 – x) = cos–1x.
The principal value branch of sec–1 is ______.
One branch of cos–1 other than the principal value branch corresponds to ______.
The principal value of the expression cos–1[cos (– 680°)] is ______.
The principal value of `sin^-1 ((-sqrt(3))/2)` is ______.
Find the value of `4tan^-1 1/5 - tan^-1 1/239`
Which of the following is the principal value branch of cos–1x?
If `cos(sin^-1 2/5 + cos^-1x)` = 0, then x is equal to ______.
The value of `cot[cos^-1 (7/25)]` is ______.
The value of `sin^-1 (sin (3pi)/5)` is ______.
If `cos(tan^-1x + cot^-1 sqrt(3))` = 0, then value of x is ______.
The set of values of `sec^-1 (1/2)` is ______.
The value of `cos^-1 (cos (14pi)/3)` is ______.
The result `tan^1x - tan^-1y = tan^-1 ((x - y)/(1 + xy))` is true when value of xy is ______.
The domain of trigonometric functions can be restricted to any one of their branch (not necessarily principal value) in order to obtain their inverse functions.
If `5 sin theta = 3 "then", (sec theta + tan theta)/(sec theta - tan theta)` is equal to ____________.
The general solution of the equation `"cot" theta - "tan" theta = "sec" theta` is ____________ where `(n in I).`
`"cos" ["tan"^-1 {"sin" ("cot"^-1 "x")}]` is equal to ____________.
