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Question
Find the principal value of cos–1x, for x = `sqrt(3)/2`.
Solution
If `cos^-1 (sqrt(3)/2)` = θ, then cos θ = `sqrt(3)/2`
Since we are considering principal branch, θ ∈ [0, π].
Also, since `sqrt(3)/2` > 0, θ being in he first quadrant
Hence `cos^-1 (sqrt(3)/2) = pi/6`
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