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Find the Principal Value of the Following: `Sec^-1(-sqrt2)` - Mathematics

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Question

Find the principal value of the following:

`sec^-1(-sqrt2)`

Solution

Let `sec^-1(-sqrt2)=y`
Then,
`secy=-sqrt2`
We know that the range of the principal value branch is [0, π] - `{pi/2}`.
Thus,

`secy=-sqrt2=sec((3pi)/4)`

`=>y=(3pi)/4in[0,pi],y!=pi/2`

Hence, the principal value of `sec^-1(-sqrt2)    is    (3pi)/4.`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.04 [Page 18]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.04 | Q 1.1 | Page 18

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