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Question
Find the principal value of the following:
`sec^-1(2)`
Solution
Let `sec^-1(2)=y`
Then,
sec y = 2
We know that the range of the principal value branch is `[0,pi]-{pi/2}.`
Thus,
`secy=2=sec(pi/3)`
`=>y=pi/3in[0,pi],y!=pi/2`
Hence, the principal value of `sec^-1(2) is pi/3. `
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