Find the value of `tan^-1 (tan (9pi)/8)`.

`tan^-1 (tan (9pi)/8) = tan^-1 tan(pi + pi/8)` = `tan^-1(tan (pi/8))` = `pi/8`

Find the value of tan-1(tan 9π8). - Mathematics

Question

Find the value of $\tan^{- 1} (\tan \frac{9 π}{8})$ .

Sum

Solution

$\tan^{- 1} (\tan \frac{9 π}{8}) = \tan^{- 1} \tan (π + \frac{π}{8})$

= $\tan^{- 1} (\tan (\frac{π}{8}))$

= $\frac{π}{8}$

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Inverse Trigonometric Functions - Inverse Trigonometric Functions - Principal Value Branch

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Chapter 2: Inverse Trigonometric Functions - Solved Examples [Page 21]

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Chapter 2 Inverse Trigonometric Functions
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Find the value of tan-1(tan 9π8). - Mathematics

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