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For the Principal Value, Evaluate of the Following: `Sin^-1(-sqrt3/2)+Cos^-1(Sqrt3/2)` - Mathematics

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Question

For the principal value, evaluate of the following:

`sin^-1(-sqrt3/2)+cos^-1(sqrt3/2)`

Solution

`sin^-1(-sqrt3/2)+cos^-1(sqrt3/2)`

`=sin^-1{sin(-pi/2)}+cos^-1(cos  pi/6)`

`=-pi/3+pi/6`      `[because"Range of sine is"[-pi/2,pi/2];  -pi/3 in [-pi/2, pi/2] "and range of cosine is" [0,pi]  ;  pi/6 in [0, pi]]`

`=-pi/6`

`therefore sin^-1(-sqrt3/2)+cos^-1(sqrt3/2)=-pi/6`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.02 [Page 10]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.02 | Q 5.4 | Page 10

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