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प्रश्न
Find the value of `tan^-1(x/y) + tan^-1((y - x)/(y + x))`
उत्तर
`tan^-1(x/y) + tan^-1((y - x)/(y + x))`
= `tan^-1(x/y) + tan^-1((1 - x/y)/(1 + x/y))`
= `tan^-1(x/y) + tan^-1(1) - tan^-1(x/y)`
= `tan^-1(1)`
= `π/4`
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