Advertisements
Advertisements
प्रश्न
All trigonometric functions have inverse over their respective domains.
पर्याय
True
False
उत्तर
This statement is False.
Explanation:
We know that all inverse trigonometric functions are restricted over their domains.
APPEARS IN
संबंधित प्रश्न
Find the principal values of `sin^(-1) (-1/2)`
Find the principal value of cosec−1 (2)
Find the principal value of `cos^(-1) (-1/2)`
Find the principal value of tan−1 (−1)
Prove that:
`tan^-1 ((sqrt(1 + x) - sqrt(1 - x))/(sqrt(1 + x) + sqrt(1 - x))) = pi/4 - 1/2 cos^-1 x`, for `- 1/sqrt2 <= x <= 1`
[Hint: put x = cos 2θ]
Find the principal value of the following: cosec- 1(2)
Find the principal value of the following: sin-1 `(1/sqrt(2))`
Evaluate the following:
`"cosec"^-1(-sqrt(2)) + cot^-1(sqrt(3))`
Prove the following:
`cos^-1(3/5) + cos^-1(4/5) = pi/(2)`
Prove the following:
`tan^-1(1/2) + tan^-1(1/3) = pi/(4)`
Prove that `2 tan^-1 (3/4) = tan^-1(24/7)`
Prove that cot−1(7) + 2 cot−1(3) = `pi/4`
Find the principal value of `cos^-1 sqrt(3)/2`
Find the principal value of cosec–1(– 1)
If `sin^-1 3/5 + cos^-1 12/13 = sin^-1 P`, then P is equal to ______
`tan[2tan^-1 (1/3) - pi/4]` = ______.
`cos(2sin^-1 3/4+cos^-1 3/4)=` ______.
If `3sin^-1((2x)/(1 + x^2)) - 4cos^-1((1 - x^2)/(1 + x^2)) + 2tan^-1((2x)/(1 - x^2)) = pi/3`, then x is equal to ______
The domain of the function y = sin–1 (– x2) is ______.
Show that `cos(2tan^-1 1/7) = sin(4tan^-1 1/3)`
`"cos"^-1 ["cos" (2 "cot"^-1 (sqrt2 - 1))] =` ____________.
`"cos" ["tan"^-1 {"sin" ("cot"^-1 "x")}]` is equal to ____________.
The number of solutions of sin–1x + sin–1(1 – x) = cos–1x is
If `(-1)/sqrt(2) ≤ x ≤ 1/sqrt(2)` then `sin^-1 (2xsqrt(1 - x^2))` is equal to
Domain and Rariges of cos–1 is:-
Find the principal value of `cot^-1 ((-1)/sqrt(3))`
If f'(x) = x–1, then find f(x)
If sin–1a + sin–1b + sin–1c = π, then find the value of `asqrt(1 - a^2) + bsqrt(1 - b^2) + csqrt(1 - c^2)`.
sin [cot–1 (cos (tan–1 x))] = ______.
