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प्रश्न
Evaluate:
`inte^x "cosec" x(1 - cot x)dx`
उत्तर
`inte^x "cosec" x(1 - cot x)dx`
= `int e^x("cosec" x - "cosec" x . cot x)dx`
= `int e^x("cosec" x + (-"cosec" x . cot x))dx` ...`[∵ inte^x(f(x) + f^'(x))dx = e^xf(x) + c]`
= `e^x"cosec" x + c`
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