Advertisements
Advertisements
प्रश्न
Find the value of the following:
sin2 30° – 2 cos3 60° + 3 tan4 45°
उत्तर
sin 30° = `1/2`, cos 60° = `1/2`, tan 45° = 1
sin2 30° – 2 cos3 60° + 3 tan4 45°
= `(1/2)^2 - 2(1/2)^3 + 3(1)^4`
= `(1/4) - 2(1/8) + 3`
= `(1/4) - (1/4) + 3`
= 3
APPEARS IN
संबंधित प्रश्न
`(2 tan 30°)/(1-tan^2 30°)` = ______.
Prove the following
`(tan (90 - A) cot A)/(cosec^2 A) - cos^2 A =0`
Evaluate: `4(sin^2 30 + cos^4 60^@) - 2/3 3[(sqrt(3/2))^2 . [1/sqrt2]^2] + 1/4 (sqrt3)^2`
Evaluate: `sin 50^@/cos 40^@ + (cosec 40^@)/sec 50^@ - 4 cos 50^@ cosec 40^@`
Evaluate: `cos 58^@/sin 32^@ + sin 22^@/cos 68^@ - (cos 38^@ cosec 52^@)/(tan 18^@ tan 35^@ tan 60^@ tan 72^@ tan 65^@)`
find the value of: sin2 30° + cos2 30°+ cot2 45°
Prove that:
cosec2 45° - cot2 45° = 1
If sec A = cosec A and 0° ∠A ∠90°, state the value of A
Find the value of the following:
(sin 90° + cos 60° + cos 45°) × (sin 30° + cos 0° – cos 45°)
If 2 sin 2θ = `sqrt(3)` then the value of θ is
