Advertisements
Advertisements
प्रश्न
If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is
पर्याय
0.235
0.707
1.414
0.471
उत्तर
Given that`sqrt2 = 1.414` .We need to find `sqrt6 - sqrt3`.
We can factor out from the given expression, to get
`sqrt6 - sqrt3 = sqrt3(sqrt2 - 1)`.
Putting the value of`sqrt2`, we get
`sqrt3 (sqrt2-1) = sqrt3(1.4142 - 1)`
`=1.732xx0.4142`
`= 0.7174`
Hence the value of expression must closely resemble be`0.707.`
APPEARS IN
संबंधित प्रश्न
Simplify the following:
`(5xx25^(n+1)-25xx5^(2n))/(5xx5^(2n+3)-25^(n+1))`
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt2/sqrt3)^5(6/7)^2`
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Show that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
Show that:
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
Find the value of x in the following:
`(root3 4)^(2x+1/2)=1/32`
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Write the value of \[\sqrt[3]{125 \times 27}\].
