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If √ 2 = 1 . 414 , Then the Value of √ 6 − √ 3 Upto Three Places of Decimal is - Mathematics

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प्रश्न

If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is

विकल्प

  •  0.235

  • 0.707

  • 1.414

  • 0.471

MCQ

उत्तर

Given that`sqrt2 = 1.414` .We need to find `sqrt6 - sqrt3`.

We can factor out from the given expression, to get

 `sqrt6 - sqrt3 = sqrt3(sqrt2 - 1)`.

Putting the value of`sqrt2`, we get

`sqrt3 (sqrt2-1) = sqrt3(1.4142 - 1)`

                      `=1.732xx0.4142`

                      `= 0.7174`

Hence the value of expression must closely resemble be`0.707.`

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अध्याय 3: Rationalisation - Exercise 3.4 [पृष्ठ १८]

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आरडी शर्मा Mathematics [English] Class 9
अध्याय 3 Rationalisation
Exercise 3.4 | Q 22 | पृष्ठ १८

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