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प्रश्न
If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.
उत्तर
`((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y`
⇒ `((b^6)/( a^3))^7 ÷ ((a^5)/(b^8))^-5 = a^x . b^y`
⇒ `((b^6)/( a^3))^7 ÷ ((b^8)/(a^5))^5 = a^x . b^y`
⇒ `((b^42)/(a^21)) ÷ ((b^40)/(a^25)) = a^x . b^y`
⇒ `((b^42)/(a^21)) xx ((a^25)/(b^40)) = a^x . b^y`
⇒ b2 x a4 = ax x by
⇒ x = 4 and y = 2
⇒ x + y = 4 + 2 = 6
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