Advertisements
Advertisements
प्रश्न
If A and B are acute angles such that tan A = 1/2, tan B = 1/3 and tan (A + B) = `(tan A + tan B)/(1- tan A tan B)` A + B = ?
उत्तर
`tan A = 1/2, tan B= 1/3`
tan (A + B) = `(tan A + tan B)/(1- tan A tan B)`
`Tan (A + B) = (1/2 + 1/3)/(1 - 1/2.1/3) = (5/6)/(1 - 1/6) = 1`
Tan (A + B) = Tan 45°
∴ A + B = 45°
APPEARS IN
संबंधित प्रश्न
In ∆PQR, right-angled at Q, PQ = 3 cm and PR = 6 cm. Determine ∠P and ∠R.
In a ΔABC , ∠B = 90° , AB = 12 cm and BC = 5 cm Find
(i) cos A (ii) cosec A (iii) cos C (iv) cosec C
Verify each of the following:
(iii) `2 sin 30^0 cos 30^0`
Given : sin A = `(3)/(5)` , find : (i) tan A (ii) cos A
In triangle ABC, ∠B = 90° and tan A = 0.75. If AC = 30 cm, find the lengths of AB and BC.
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
tanB = `(8)/(15)`
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: cos C
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: tan B.
In the given figure, ΔABC is right angled at B.AD divides BC in the ratio 1 : 2. Find
(i) `("tan"∠"BAC")/("tan"∠"BAD")` (ii) `("cot"∠"BAC")/("cot"∠"BAD")`
If cosec θ = `(29)/(20)`, find the value of: `("sec" θ)/("tan" θ - "cosec" θ)`
