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प्रश्न
If sin θ = cos (θ – 45°), where θ – 45° are acute angles, find the degree measure of θ
उत्तर
Sin θ = cos (θ – 45°)
Cos θ = cos (90 – θ)
Cos (θ – 45°) = sin (90° - (θ – 45°)) = sin (90 – θ + 45°)
Sin θ(135 – θ)
θ = 135 – θ
2θ = 135
∴ θ = 135°/2
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