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प्रश्न
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cotA = `(1)/(11)`
उत्तर
cotA = `(1)/(11)`
cotA = `(1)/"tanA" ="Base"/"Perpendicular"`
By Pythagoras theorem, we have
(Hypotenuse)2 = (Perpendicular)2 + (Base)2
(Hypotenuse) = `sqrt(("Perpendicular")^2 + ("Base")^2`
= `sqrt((11)^2 + (1)^2`
= `sqrt(121 + 1)`
= `sqrt(122)`
cosA = `"Base"/"Hypotenuse" = (1)/sqrt(122)`
tanA = `"Perpendicular"/"Base"` = 11
secA = `(1)/"cosA" = sqrt(122)`
sinA = `"Perpendicular"/"Hypotenuse" = (11)/sqrt(122)`
cosecA = `(1)/"sinA" = sqrt(122)/(11)`.
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