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प्रश्न
If sec 2A = cosec (A – 42°) where 2A is an acute angle. Find the value of A.
उत्तर
We know that (sec (90 – θ)) = cosec θ
Sec 2A = sec (90 – (A – 42))
Sec 2A = sec (90 – A + 42)
Sec 2A = sec (132 – A)
Now equating both the angles we get
2A = 132 – A
`3A = 132/3`
A= 44
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