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प्रश्न
In an isosceles triangle ABC, AB = BC = 6 cm and ∠B = 90°. Find the values of cos C
उत्तर
ΔABC is an isosceles right-angled triangle.
∴ AC2
= AB2 + BC2
= 62 + 62
= 36 + 36
= 72
⇒ AC = `6sqrt(2)"cm"`
cos C
= `"BC"/"AC"`
= `(6)/(6sqrt(2)`
= `(1)/sqrt(2)`.
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