Advertisements
Advertisements
प्रश्न
If sin A + cosec A = 2;
Find the value of sin2 A + cosec2 A.
उत्तर
sin A + cosec A = 2
Squaring both sides
(sin A + cosecA)2 = 22
sin2 A + cosec2 A + 2sin A . cosecA = 4
sin2 A + cosec2A + 2sin A. `1/sin "A"` = 4
sin2 A + cosec2 A = 2
APPEARS IN
संबंधित प्रश्न
If 2θ + 45° and 30° − θ are acute angles, find the degree measure of θ satisfying Sin (20 + 45°) = cos (30 - θ°)
If sin θ = ` (a^2 - b^2)/(a^2+b^2)`find all the values of all T-ratios of θ .
If sin A = `9/41` find all the values of cos A and tan A
Evaluate:
`(5 cos^2 60^circ + 4 sec^2 30^circ - tan^2 45^circ)/(sin^2 30^circ + cos^2 30^circ)`
If A = 600 and B = 300, verify that:
(i) sin (A – B) = sin A cos B – cos A sin B
Form the following figure, find the values of:
- cos B
- tan C
- sin2B + cos2B
- sin B. cos C + cos B. sin C
From the following figure, find:
(i) y
(ii) sin x°
(iii) (sec x° - tan x°) (sec x° + tan x°)
If 2 sin x = `sqrt3` , evaluate.
(i) 4 sin3 x - 3 sin x.
(ii) 3 cos x - 4 cos3 x.
If sin A = `(sqrt3)/(2)` and cos B = `(sqrt3)/(2)` , find the value of : `(tan"A" – tan"B")/(1+tan"A" tan"B")`
In the given figure, PQR is a triangle, in which QS ⊥ PR, QS = 3 cm, PS = 4 cm and QR = 12 cm, find the value of: 4sin2R - `(1)/("tan"^2"P")`
