Advertisements
Advertisements
प्रश्न
Using the formula, sin A = `sqrt((1-cos 2A)/2) ` find the value of sin 300, it being given that cos 600 = `1/2`
उत्तर
A = 300
⇒ 2A = 2 × 300 = 600
By substituting the value of the given T-ratio, we get:
sin A =`sqrt((1- cos 2A)/2)`
sin `30^0 = sqrt((1-cos 60^0)/2) = sqrt(1-1/2)/2 = sqrt((1/2)/2) = sqrt(1/4) =1/2`
∴ sin `30^0 = 1/2`
APPEARS IN
संबंधित प्रश्न
In a ΔABC, right angled at A, if tan C = `sqrt3` , find the value of sin B cos C + cos B sin C.
If `sin (A – B) = 1/2` and `cos (A + B) = 1/2`, `0^@` < A + `B <= 90^@`, A > B Find A and B.
If sin ∝ = `1/2` prove that (3cos∝ - `4cos^2` ∝)=0
Evaluate:
cos450 cos300 + sin450 sin300
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cosB = `(4)/(5)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
sinB = `sqrt(3)/(2)`
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: sinA
In ΔABC, ∠B = 90°. If AB = 12units and BC = 5units, find: tan A
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of `(1)/("sin"^2 x) - (1)/("tan"^2 x)`
From the given figure, find the values of sec B
