Advertisements
Advertisements
प्रश्न
Using the formula, sin A = `sqrt((1-cos 2A)/2) ` find the value of sin 300, it being given that cos 600 = `1/2`
उत्तर
A = 300
⇒ 2A = 2 × 300 = 600
By substituting the value of the given T-ratio, we get:
sin A =`sqrt((1- cos 2A)/2)`
sin `30^0 = sqrt((1-cos 60^0)/2) = sqrt(1-1/2)/2 = sqrt((1/2)/2) = sqrt(1/4) =1/2`
∴ sin `30^0 = 1/2`
APPEARS IN
संबंधित प्रश्न
If 3 cot A = 4, Check whether `((1-tan^2 A)/(1+tan^2 A)) = cos^2 "A" - sin^2 "A"` or not.
Evaluate:
cos450 cos300 + sin450 sin300
Evaluate:
`2cos^2 60^0+3 sin^2 45^0 - 3 sin^2 30^0 + 2 cos^2 90 ^0`
Evaluate:
`(sin^2 30^0 + 4 cot^2 45^0-sec^2 60^0)(cosec^2 45^0 sec^2 30^0)`
Show that:
(i)` (1-sin 60^0)/(cos 60^0)=(tan60^0-1)/(tan60^0+1)`
In each of the following, one trigonometric ratio is given. Find the values of the other trigonometric.
cosec C = `sqrt(10)`
If 8 tanθ = 15, find (i) sinθ, (ii) cotθ, (iii) sin2θ - cot2θ
In the given figure, AD is the median on BC from A. If AD = 8 cm and BC = 12 cm, find the value of sin x
In a right-angled triangle PQR, ∠PQR = 90°, QS ⊥ PR and tan R =`(5)/(12)`, find the value of sin ∠PQS
From the given figure, find the values of cos C
