Advertisements
Advertisements
प्रश्न
In the given figure, ∆AHK is similar to ∆ABC. If AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find AC.
उत्तर
Given: `Δ AHK ∼ Δ ABC`
AK = 10 cm
BC = 3.5 cm
HK = 7 cm
To find: AC
Since ,` Δ AHK ∼ Δ ABC `so their corresponding sides are proportional.
`(AC)/(AK)=(BC)/(HK)`
`(AC)/10=3.5/7`
`AC= 5 cm`
APPEARS IN
संबंधित प्रश्न
the below given figure, a triangle ABC is drawn to circumscribe a circle of radius 3 cm, such that the segments BD and DC are respectively of lengths 6 cm and 9 cm. If the area of ΔABC is 54 cm2, then find the lengths of sides AB and AC.
In below Figure, ΔABC is right angled at C and DE ⊥ AB. Prove that ΔABC ~ ΔADE and Hence find the lengths of AE and DE.
In a ΔABC, AD is the bisector of ∠A.
If AB = 10cm, AC = 14cm and BC = 6cm, find BD and DC.
A 13m long ladder reaches a window of a building 12m above the ground. Determine the distance of the foot of the ladder from the building.
In each of the figures [(i)-(iv)] given below, a line segment is drawn parallel to one side of the triangle and the lengths of certain line-segment are marked. Find the value of x in each of the following :
In the given figure,
AB || DC prove that
DM × BV = BM ✕ DU
Prove that in an equilateral triangle, three times the square of a side is equal to four times the square of its altitudes.
∆ABC and ∆BDE are two equilateral triangles such that D is the mid-point of BC. The ratio of the areas of triangle ABC and BDE is
If ABC is a right triangle right-angled at B and M, N are the mid-points of AB and BC respectively, then 4(AN2 + CM2) =
If ∆ABC ∼ ∆DEF such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ∆DEF is 25 cm, then the perimeter of ∆ABC is
