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प्रश्न
Solve the differential equation `"dy"/"dx" + y/x` = x2.
उत्तर
The equation is of the type `"dy"/"dx" + "Py"` = Q, which is a linear differential equation.
Now I.F. = `int 1/x "d"x`
= elogx = x.
Therefore, solution of the given differential equation is
y.x = `int x x^2 "d"x`
i.e. yx = `x^4/4 + "c"`
Hence y = `x^3/4 + "c"/x`.
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