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Question
A 13m long ladder reaches a window of a building 12m above the ground. Determine the distance of the foot of the ladder from the building.
Solution
Let AB and AC be the ladder and height of the building.
It is given that :
AB = 13 m and AC = 12 m
We need to find distance of the foot of the ladder from the building, i.e, BC.
In right-angled triangle ABC, we have:
`AB^2=AC^2+BC^2`
⟹ `BC=sqrt(13^2-12^2)`
=`sqrt(169-144)`
`=sqrt25`
=5 m
Hence, the distance of the foot ladder from the building is 5 m
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