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Question
A die is tossed twice. A 'success' is getting an even number on a toss. Find the variance of number of successes.
Solution
\[\text{ We have, } \]
\[p = \text{ probability of getting an even number on a toss } = \frac{3}{6} = \frac{1}{2} \text{ and } \]
\[q = 1 - p = 1 - \frac{1}{2} = \frac{1}{2}\]
\[\text{ Let X denote a success of getting an even number on a toss . Then } , \]
\[\text{ X follows binomial distribution with parameters n = 2 and } p = \frac{1}{2}\]
\[ \therefore Var\left( X \right) = \text{ npq } = 2 \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{2}\]
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