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A Galvanometer Has a Resistance of 16ω. It Shows Full Scale Deflection, When a Current of 20 Ma is Passed Through It. the Only Shunt Resistance Available is 0.06 Which is Not Ap - Physics

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Question

A galvanometer has a resistance of 16Ω. It shows full scale deflection, when a current of 20 mA is passed through it. The only shunt resistance available is 0.06  which is not appropriate to convert a galvanometer into an ammeter. How much resistance should be connected in series with the coil of galvanometer, so that the range of ammeter is 8 A?

Sum

Solution

Let ‘X’ be the resistance connected in series with galvanometer.
Since S is not sufficient for I = 10 A
G = 16 Ω,

`"I"_"g"/"I" = "S"/(("G + X") + "S")`

∴ (G + X) + S = `"I"/"I"_"g""S"`

∴ `(16 + "X" + 0.06) = 8/(2 xx 10^-2) xx 0.06`

∴ (16 + X + 0.06) = 24

∴ X = 24 - 16.06

∴ X = 7.94

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2012-2013 (October)

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