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Question
A gas mixture consists of molecules of types A, B and C with masses mA > mB > mC. Rank the three types of molecules in decreasing order of average K.E.
Solution
The average K.E. will be the same, as conditions of temperature and pressure are the same.
Now as, `v_(rms) = sqrt((3pV)/M) = sqrt((3RT)/M)`
= `sqrt((3RT)/(mN)) = sqrt((3kT)/m)`
Where, M = Molar mass of the gas
m = Mass of each molecular of the gas
R = Gas constant
Clearly, `v_(rms) ∝ sqrt(1/m)`
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