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An aircraft of wing span of 50 m flies horizontally in the Earth's magnetic field of 6 x 10-5 T at a speed of 400 m/s. Calculate the emf generated between the tips of the wings of the aircraft. - Physics

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Question

An aircraft of wing span of 50 m flies horizontally in the Earth's magnetic field of 6 x 10-5 T at a speed of 400 m/s. Calculate the emf generated between the tips of the wings of the aircraft.

Numerical

Solution 1

Data: l = 50 m, B = 6 x 10-5 T, v = 400 m/s

The magnitude of the induced emf,

|e| = Blv = (6 × 10-5)(400)(50) = 1.2 V

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Solution 2

Induced emf between tips of wings,

e = Blv

= 6 × 10-5 × 50 × 400

= 1.2 V

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Chapter 12: Electromagnetic induction - Exercises [Page 287]

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Balbharati Physics [English] 12 Standard HSC Maharashtra State Board
Chapter 12 Electromagnetic induction
Exercises | Q 9 | Page 287
SCERT Maharashtra Physics [English] 12 Standard HSC
Chapter 12 Electromagnetic Induction
Very Short Answer | Q 6

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