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Question
Find `"dy"/"dx"` if, y = `5^(("x" + log"x"))`
Solution
y = `5^(("x" + log"x"))`
Differentiating both sides w.r.t.x, we get
`"dy"/"dx" = "d"/"dx"[5^(("x" + log"x"))]`
`= 5^(("x" + log"x")) * log 5 * "d"/"dx" ("x" + log"x")`
∴ `"dy"/"dx" = 5^(("x" + log"x")) * log 5 * (1 + 1/"x")`
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