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Karnataka Board PUCPUC Science Class 11

Find the Ratio of the Linear Momenta of Two Particles of Masses 1.0 Kg and 4.0 Kg If Their Kinetic Energies Are Equal. - Physics

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Question

Find the ratio of the linear momenta of two particles of masses 1.0 kg and 4.0 kg if their kinetic energies are equal.

Sum

Solution

Let the masses of the two particles be m1 and m2.
Given:
m1 = 1 kg
m2 = 4 kg

Now,
Kinetic energy of the first particle = Kinetic energy of the second particle

\[\left( \frac{1}{2} \right) m_1 v_1^2 = \left( \frac{1}{2} \right) m_2 v_2^2 \]

\[ \Rightarrow \frac{m_1}{m_2} = \frac{v_2^2}{v_1^2}\]

\[ \Rightarrow \frac{v_2}{v_1} = \sqrt{\frac{m_1}{m_2}}\]

\[ \Rightarrow \frac{v_1}{v_2} = \sqrt{\frac{m_2}{m_1}}\]

\[\text{ The ratio of linear momenta (mv) of the two particles,} \]

\[\frac{P_1}{P_2} = \frac{m_1 v_1}{m_2 v_2} = \frac{m_1}{m_2}\sqrt{\frac{m_2}{m_1}}\]

\[ = \sqrt{\frac{m_1}{m_2}} = \sqrt{\frac{1}{4}} = \frac{1}{2}\]

\[ \Rightarrow P_1 : P_2 = 1: 2\]

Therefore, the ratio of linear momenta is 1:2.

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Chapter 9: Centre of Mass, Linear Momentum, Collision - Exercise [Page 160]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 9 Centre of Mass, Linear Momentum, Collision
Exercise | Q 15 | Page 160

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