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Question
Find the area of a sector of a circle of radius 28 cm and central angle 45°.
Solution
Given that, Radius of a circle, r = 28 cm
And measure of central angle θ = 45°
∴ Area of a sector of a circle = `(π"r"^2)/360^circ xx θ`
= `22/7 xx (28)^2/360^circ xx 45^circ`
= `(22 xx 28 xx 28)/7 xx 45^circ/360^circ`
= `22 xx 4 xx 28 xx 1/8`
= 22 × 14
= 308 cm2
Hence, the required area of a sector of a circle is 3082 cm.
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