English

Find the mean deviation about the mean for the data. xi 5 10 15 20 25 fi 7 4 6 3 5 - Mathematics

Advertisements
Advertisements

Question

Find the mean deviation about the mean for the data.

xi 5 10 15 20 25
fi 7 4 6 3 5
Sum

Solution

xi fi fi xi `|"x"_"i" - overline "x"|` `"f"_"i"|"x"_"i" - overline "x"|`
5 7 35 9 63
10 4 40 4 16
15 6 90 1 6
20 3 60 6 18
25 5 125 11 55
Sum 25 350 - 158

`overline "x" = (sum"f"_"i""x"_"i")/(sum"f"_"i")` 

= `350/25`

= 14

Mean Deviation = `(sum"f"_"i" |"x"_"i" - overline"x"|)/"N"`

= `158/25`

= 6.32

shaalaa.com
  Is there an error in this question or solution?
Chapter 15: Statistics - Exercise 15.1 [Page 360]

APPEARS IN

NCERT Mathematics [English] Class 11
Chapter 15 Statistics
Exercise 15.1 | Q 5 | Page 360

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the mean deviation about the mean for the data.

4, 7, 8, 9, 10, 12, 13, 17


Find the mean deviation about the median for the data.

13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


Find the mean deviation about the median for the data.

36, 72, 46, 42, 60, 45, 53, 46, 51, 49


Find the mean deviation about the median for the data.

xi 5 7 9 10 12 15
fi 8 6 2 2 2 6

Find the mean deviation about the mean for the data.

Height in cms Number of boys
95 - 105 9
105 - 115 13
115 - 125 26
125 - 135 30
135 - 145 12
145 - 155 10

Find the mean deviation about median for the following data:

Marks Number of girls
0-10 6
10-20 8
20-30 14
30-40 16
40-50 4
50-60 2

Calculate the mean deviation about the median of the observation:

 34, 66, 30, 38, 44, 50, 40, 60, 42, 51


Calculate the mean deviation about the median of the observation:

 22, 24, 30, 27, 29, 31, 25, 28, 41, 42


Calculate the mean deviation about the median of the observation:

 38, 70, 48, 34, 63, 42, 55, 44, 53, 47

 

Calculate the mean deviation from the mean for the  data:

 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17


Calculate the mean deviation from the mean for the  data:

 38, 70, 48, 40, 42, 55, 63, 46, 54, 44a


The lengths (in cm) of 10 rods in a shop are given below:
40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2 

Find mean deviation from the mean also.

 

 


Find the mean deviation from the mean for the data:

Size 20 21 22 23 24
Frequency 6 4 5 1 4

Find the mean deviation from the mean for the data:

Classes 0-10 10-20 20-30 30-40 40-50 50-60
Frequencies 6 8 14 16 4 2

Compute mean deviation from mean of the following distribution:

Mark 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90
No. of students 8 10 15 25 20 18 9 5

The age distribution of 100 life-insurance policy holders is as follows:

Age (on nearest birth day) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5
No. of persons 5 16 12 26 14 12 6 5

Calculate the mean deviation from the median age


Find the mean deviation from the mean and from median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

The mean of 5 observations is 4.4 and their variance is 8.24. If three of the observations are 1, 2 and 6, find the other two observations.

 

The mean deviation of the series aa + da + 2d, ..., a + 2n from its mean is


The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is


The mean deviation for n observations \[x_1 , x_2 , . . . , x_n\]  from their mean \[\bar{X} \]  is given by

 
  

Let \[x_1 , x_2 , . . . , x_n\]  be n observations and  \[X\]  be their arithmetic mean. The standard deviation is given by

 

The mean deviation of the data 2, 9, 9, 3, 6, 9, 4 from the mean is ______.


Find the mean deviation about the mean of the distribution:

Size 20 21 22 23 24
Frequency 6 4 5 1 4

Find the mean deviation about the median of the following distribution:

Marks obtained 10 11 12 14 15
No. of students 2 3 8 3 4

Calculate the mean deviation about the mean for the following frequency distribution:

Class interval 0 – 4 4 – 8 8 – 12 12 – 16 16 – 20
Frequency 4 6 8 5 2

Determine mean and standard deviation of first n terms of an A.P. whose first term is a and common difference is d.


The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is ______.


When tested, the lives (in hours) of 5 bulbs were noted as follows: 1357, 1090, 1666, 1494, 1623 
The mean deviations (in hours) from their mean is ______.


The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the observations is ______.


If `barx` is the mean of n values of x, then `sum_(i = 1)^n (x_i - barx)` is always equal to ______. If a has any value other than `barx`, then `sum_(i = 1)^n (x_i - barx)^2` is ______ than `sum(x_i - a)^2`


The sum of squares of the deviations of the values of the variable is ______ when taken about their arithmetic mean.


Let X = {x ∈ N: 1 ≤ x ≤ 17} and Y = {ax + b: x ∈ X and a, b ∈ R, a > 0}. If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×