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Question
Find the value of p and q if:
`[(2p + 1 , q^2 - 2),(6 , 0)] = [(p + 3, 3q - 4),(5q - q^2, 0)]`.
Solution
2p + 1 = p + 3;
2p - p = 3 - 1
p = 2 ...(1)
q2 - 2 = 3q - 4
q2 - 3q + 2 = 0
q2 - 2q - q + 2 = 0
q(q - 2) - (q - 2) = 0
(q - 2) (q - 1) = 0 ...(2)
5q - q2 = 6
q2 - 5q + 6 = 0
(q - 3) (q - 2) = 0 ...(3)
By equation (2) and (3)
q = 2
⇒ p = 2, q = 2.
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