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Question
Find the value of `sin[2cot^-1 ((-5)/12)]`
Solution
Let `cot^-1 ((-5)/12)` = y.
Then cot y = `(-5)/12`
Now `sin[2cot^-1 ((-5)/12)]` = sin 2y
= 2siny cosy
= `2(12/13)((-5)/13)` ......`["since" cot y < 0, "so" y ∈(pi/2, pi)]`
= `(-120)/169`
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