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Question
Form the differential equation from the relation x2 + 4y2 = 4b2
Solution
Given relation is
x2 + 4y2 = 4b2
Differentiating w.r.t. x, we get
`2x + 4.2y ("d"y)/("d"x) = 0`
∴ `x + 4y ("d"y)/("d"x) = 0`, which is the required differential equation.
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