English

Given a = (2,0), (-1,7) and 1 = (1,0), (0,1) and A2 = 9a +Mi. Find M - Mathematics

Advertisements
Advertisements

Question

Given A = `[(2,0), (-1,7)] and 1 = [(1,0), (0,1)]` and A2 = 9A +mI. Find m

Sum

Solution

A2 = 9A + MI

⇒ A2 - 9A = mI ….(1)

Now, A2 = AA

= `[(2,0), (-1,7)][(2,0), (-1,7)]`

= `[(4,0), (-9,49)]`

Substituting A2 in (1), we have

A2 - 9A = mI

`=> [(4,0), (-9,49)]-9[(2,0), (-1,7)] =m[(1,0), (0,1)]`

`=> [(4,0), (-9,49)] - [(18,0), (-9,63)] = [(m,0), (0,m)]`

`=> [(-14,0), (0,-14)] = [(m,0), (0,m)]`

`=>` m = -14

shaalaa.com
  Is there an error in this question or solution?
Chapter 9: Matrices - Exercise 9 (D) [Page 132]

APPEARS IN

Selina Mathematics [English] Class 10 ICSE
Chapter 9 Matrices
Exercise 9 (D) | Q 22 | Page 132

Video TutorialsVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×