Advertisements
Advertisements
Question
If `1176=2^a3^b7^c,` find a, b and c.
Solution
First find out the prime factorisation of 1176.
It can be observed that 1176 can be written as `2^3xx3^1xx7^2.`
`1176=2^3 3^1 7^2 = 2^a3^b7^c`
Hence, a = 3, b = 1 and c = 2.
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
If a = 3 and b = -2, find the values of :
ab + ba
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt(x^-3))^5`
Prove that:
`(64/125)^(-2/3)+1/(256/625)^(1/4)+(sqrt25/root3 64)=65/16`
Find the value of x in the following:
`(3/5)^x(5/3)^(2x)=125/27`
When simplified \[( x^{- 1} + y^{- 1} )^{- 1}\] is equal to
If 9x+2 = 240 + 9x, then x =
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
Find:-
`125^(1/3)`
Find:-
`32^(2/5)`
