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If a2 + 1a2=47 and a ≠ 0 find : a+1a a3+1a3 - Mathematics

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Question

If  a2 + `1/a^2 = 47` and a ≠ 0   find :

  1. `a + 1/a`
  2. `a^3 + 1/a^3`
Sum

Solution

(i) `a + 1/a`

`a^2 + 1/a^2 = 47`

`( a + 1/a )^2 = a^2 + 1/a^2 + 2`

⇒ `( a + 1/a )^2 = 47 + 2`

⇒ `( a + 1/a )^2 = 49`

⇒ `a + 1/a = +- sqrt49`

⇒ `a + 1/a = +- 7`          ....(1)

(ii) `a^3 + 1/a^3`

`( a + 1/a )^3 = a^3 + 1/a^3 + 3( a + 1/a )`

⇒ `a^3 + 1/a^3 = ( a + 1/a )^3 - 3( a + 1/a )`

⇒ `a^3 + 1/a^3 = ( +- 7 )^3 - 3( +- 7 )`        [ From (1) ]

⇒ `a^3 + 1/a^3 = +- 322`

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Chapter 4: Expansions (Including Substitution) - Exercise 4 (B) [Page 60]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 4 Expansions (Including Substitution)
Exercise 4 (B) | Q 2 | Page 60
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