Advertisements
Advertisements
Question
If O is the centre of the circle, find the value of x in the following figure
Solution
We have
∠OAB = 35°
Then, ∠OBA = ∠OAB = 35°
In ∠AOB, by angle sum property
⇒∠AOB + ∠OAB + ∠OBA = 180°
⇒ ∠AOB = 180° - 35° - 35° = 110°
∴∠AOB + reflex ∠AOB = 360°
⇒ 110° + reflex ∠AOB = 360°
⇒ reflex ∠AOB = 360° -110° = 250°
By degree measure theorem reflex ∠AOB = 2
⇒250° = 2x
`⇒ x =( 250°)/2= 125°`
APPEARS IN
RELATED QUESTIONS
In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC.
In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.
Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.
In the below fig. O is the centre of the circle. Find ∠BAC.
If O is the centre of the circle, find the value of x in the following figure
If O is the centre of the circle, find the value of x in the following figures.
Prove that the line segment joining the mid-point of the hypotenuse of a right triangle to its opposite vertex is half the hypotenuse.
In the given figure, two congruent circles with centres O and O' intersect at A and B. If ∠AOB = 50°, then find ∠APB.
In the given figure, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD =
If ABC is an arc of a circle and ∠ABC = 135°, then the ratio of arc \[\stackrel\frown{ABC}\] to the circumference is ______.