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If tan-1(x-1x-2)+tan-1(x+1x+2)=π4, find the value of x. - Mathematics and Statistics

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Question

If `tan^-1 (("x" - 1)/("x" - 2)) + tan^-1 (("x" + 1)/("x" + 2)) = pi/4`, find the value of x.

Sum

Solution

`tan^-1 (("x" - 1)/("x" - 2)) + tan^-1 (("x" + 1)/("x" + 2)) = pi/4`

∴ `tan^-1  [("x - 1"/"x - 2" + "x + 1"/"x + 2")/(1 - ("x - 1"/"x - 2")("x + 1"/"x + 2"))] = pi/4`

∴ `(("x - 1")("x + 2") + ("x + 1")("x - 2"))/(("x - 2")("x + 2") - ("x - 1")("x + 1")) = tan  pi/4`

∴ `(("x"^2 + "x" - 2) + ("x"^2 - "x" - 2))/(("x"^2 - 4) - ("x"^2 - 1)) = 1`

∴ `("x"^2 + "x" - 2 + "x"^2 - "x" - 2)/("x"^2 - 4 - "x"^2 + 1) = 1`

∴ `(2"x"^2 - 4)/-3 = 1`

∴ 2x2 - 4 = - 3

∴ 2x2 = 1

∴ x2 = `1/2`

∴ x = `+- 1/sqrt2`.

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Chapter 3: Trigonometric Functions - Miscellaneous exercise 3 [Page 110]

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Balbharati Mathematics and Statistics 1 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
Chapter 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 25 | Page 110

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