Advertisements
Advertisements
Question
If tan A = cot B, prove that A + B = 90°.
Theorem
Advertisements
Solution
∵ tan A = cot B
tan A = tan (90° – B)
A = 90° – B
A + B = 90°. Proved
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Prove the following trigonometric identities.
(secθ + cosθ) (secθ − cosθ) = tan2θ + sin2θ
Solve.
sin15° cos75° + cos15° sin75°
Use tables to find cosine of 2° 4’
If A and B are complementary angles, prove that:
cot B + cos B = sec A cos B (1 + sin B)
What is the maximum value of \[\frac{1}{\sec \theta}\]
In the case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
cos(90° - A) · sec 77° = 1
Find the value of the following:
tan 15° tan 30° tan 45° tan 60° tan 75°
Find the value of the following:
sin 21° 21′
If sin 3A = cos 6A, then ∠A = ?
In ∆ABC, `sqrt(2)` AC = BC, sin A = 1, sin2A + sin2B + sin2C = 2, then ∠A = ? , ∠B = ?, ∠C = ?
