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Question
If `(x^2 + y^2)/(x^2 - y^2) = 2 1/8`, find: `x/y`
Solution
Given, `(x^2 + y^2)/(x^2 - y^2) = 2 1/8`
`(x^2 + y^2)/(x^2 - y^2) = 17/8`
Applying componendo and dividendo,
`(x^2 + y^2 + x^2 - y^2)/(x^2 + y^2 - x^2 + y^2) = (17 + 8)/(17 - 8)`
`(2x^2)/(2y^2) = 25/9`
`x^2/y^2 = 25/9`
`x/y = 5/3 = 1 2/3`
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