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In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB. - Geometry Mathematics 2

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Question

In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB.

Sum

Solution

Let CD be the median drawn from the vertex C to side AB.

`"BD" = 1/2 × "AB"`              ...(D is the midpoint of AB)

∴ BD = `1/2 × 10`

∴ BD = 5 units

In ∆ABC,

seg CD is the median.                 ...(Given)

By Apollonius theorem,

∴ AC2 + BC2 = 2CD2 + 2BD2

∴ 72 + 92 = 2CD2 + 2(5)2

∴ 49 + 81 = 2CD2 + 2 × 25

∴ 130 = 2CD2 + 50

∴ 2CD= 130 − 50

∴ CD= `80/2`

∴ CD= 40
Taking square root of both sides,
∴ CD = `sqrt(40)`
∴ CD = `sqrt(4 × 10)`
∴ CD = `2sqrt(10)`
Hence, the length of the median drawn from point C to side AB is `2sqrt(10)` units.
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