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Question
A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.
Solution
Let BC = 18 m be the flag pole and its shadow be AB = 9.6 m.
The distance of the top of the pole, C from the far end i.e., A of the shadow is AC.
In right angled ∆ABC,
AC2 = AB2 + BC2 ...[By pythagoras theorem]
⇒ AC2 = (9.6)2 + (18)2
⇒ AC2 = 92.16 + 324
⇒ AC2 = 416.16
∴ AC = `sqrt(416.16)` = 20.4 m
Hence, the required distance is 20.4 m.
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