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A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow. - Mathematics

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प्रश्न

A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.

योग

उत्तर

Let BC = 18 m be the flag pole and its shadow be AB = 9.6 m.

The distance of the top of the pole, C from the far end i.e., A of the shadow is AC.


In right angled ∆ABC,

AC2 = AB2 + BC2   ...[By pythagoras theorem]

⇒ AC2 = (9.6)2 + (18)2

⇒ AC2 = 92.16 + 324

⇒ AC2 = 416.16

∴ AC = `sqrt(416.16)` = 20.4 m

Hence, the required distance is 20.4 m.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Triangles - Exercise 6.4 [पृष्ठ ७४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 6 Triangles
Exercise 6.4 | Q 7 | पृष्ठ ७४

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