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Question
In ∆ABC, the bisector of ∠A intersects BC in D. If AB = 18 cm, AC = 15 cm and BC = 22 cm, find BD.
Solution
We have to find the value of BD.
Given AB = 18cm ,AC= 15cm and `BC = 22cm`.
In Δ ABC, AD the bisector of `∠ A.`.
`(AB)/(AC)=(BD)/(DC)`
`(AB)/(AC)=(BD)/(BC-BD)`
`18/15=(BD)/(22-BD)`
On cross multiplication, we get
`6(22-BD)=5xxBD`
`132-6BD=5BD`
`132=5BD+6BD`
`132=11BD`
`BD=12cm`
Hence, the value of BD is 12 cm.
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