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Question
In ΔABC, D and E are points on the sides AB and AC respectively such that DE || BC
If AD = 8cm, AB = 12 cm and AE = 12 cm, find CE.
Solution
We have,
AD = 8cm, AB = 12 cm
∴ BD = AB – AD
= 12 – 8
⇒ BD = 4 cm
And, DE || BC
Therefore, by basic proportionality theorem, we have,
`"AD"/"DB"="AE"/"CE"`
`rArr8/4=12/"CE"`
`rArr"CE"=(12xx4)/8=12/2`
⇒ CE = 6cm
∴ CE = 6cm
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