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Question
Find the length of a diagonal of a rectangle whose adjacent sides are 30cm and 16cm.
Solution
Let ABCD be the rectangle with diagonals AC and BD meeting at O.
According to the question:
AB = CD = 30 cm and BC = AD = 16 cm
Applying Pythagoras theorem in right-angled triangle ABC, we get:
`AC^2=AB^2+BC^2=30^2+16^2=900+256=1156`
`AC=sqrt1156=34cm`
Diagonals of a rectangle are equal.
Therefore, AC = BD = 34 cm
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