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Question
In the following figure, shows a kite in which BCD is the shape of a quadrant of a circle of radius 42 cm. ABCD is a square and Δ CEF is an isosceles right angled triangle whose equal sides are 6 cm long. Find the area of the shaded region.
Solution
We will find the area of the shaded region as shown below,
Area of the shaded region = area of quadrant + area of isosceles triangle ……..(1)
`∴" Area of shaded region"=90/360xxpixx42^2+1/2xx6xx6`
`∴" Area of shaded region"=1/4xxpixx42^2+1/2xx36`
Substituting `pi=22/7` we get,
`∴ "Area of shaded region"=1/4xx22/7xx42^2+1/2xx36`
`∴ "Area of shaded region"=1/2xx11xx6xx42+18`
`∴ "Area of shaded region"=11xx3xx42+18`
`∴ "Area of shaded region"=1386+18`
`∴ "Area of shaded region"=1404`
Therefore, area of the shaded region is `1404 cm^2`
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