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Question
In the following figure, the square ABCD is divided into five equal parts, all having same area. The central part is circular and the ines AE, GC, BF and HD lie along the diagonals AC and BD of the square. If AB = 22 cm, find:
the circumference of the central part.
Solution
We have a square ABCD.
We have,
`AB=22 cm`
We have to find the perimeter of the triangle. We have a relation as,
Area of circular region=`1/5("Area of" ABCD)`
So,
`pir^2=1/5(22)^2`
`r=22/sqrt5pi`
`=5.56`
So perimeter of the circular region,
`=2pi r`
`=(22)22/7(22/sqrt(5pi))`
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